Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 3, 2018 15:40:30 GMT -5
Equation and quote per '77 rules and quoted without permission ... Okay. So ... given this is the only information one might have for calculating in-system travel (travell?) times, how might this work? Assuming 238,900 miles from Earth to the moon (mean distance, rounded) and 2 gee acceleration. T = 2 x (square root of [238,900/2]) and using PEMDAS T = 2 x (square root of [119450]) T = 2 x (346) T = 691 691 ... what? I'm sorry to be a deadglow here, but can someone shed light on how to make this equation work?
|
|
|
Post by True Black Raven on Apr 3, 2018 16:24:13 GMT -5
Equation and quote per '77 rules and quoted without permission ... Okay. So ... given this is the only information one might have for calculating in-system travel (travell?) times, how might this work? Assuming 238,900 miles from Earth to the moon (mean distance, rounded) and 2 gee acceleration. T = 2 x (square root of [238,900/2]) and using PEMDAS T = 2 x (square root of [119450]) T = 2 x (346) T = 691 691 ... what? I'm sorry to be a deadglow here, but can someone shed light on how to make this equation work? Not looking at the rules and just taking a shot in the dark solely based on the quote I am thinking 691 minutes which equals 11 hours and 31 minutes.
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 3, 2018 18:46:43 GMT -5
Not looking at the rules and just taking a shot in the dark solely based on the quote I am thinking 691 minutes which equals 11 hours and 31 minutes. Okay, I see how you arrived at that figure. I got similar results. But, then? To check my work I looked at the Typical Travel Times table in Book 2, page 1 and see the typical travel time for 100,000 miles at 1-gee to be 2.3 hours. So ... twice as for at 2-gee (a bit less than the actual distance) is still way less than 11+ hours. Even if one triples that figure it is still less. To triple-check. I cross-referenced with the '81 version of the rules. Converting miles to kilometers for the mean distance from Earth to the moon I get 384,472 clicks. Then, looking at the Typical Travel Times tables in Book 2, page 10? I see 129-149 minutes for a similar distance (300,000 and 400,000, respectively). So ... from a bit over 2 hours to less than 3 hours. These figures seem to more or less line up with table values in '77 Traveller. I'm out to sea on this one. I know I'm a proponent of run it your way but I would at least like to understand the rules as written before I head off into my own territory.
|
|
|
Post by True Black Raven on Apr 3, 2018 20:35:18 GMT -5
Not looking at the rules and just taking a shot in the dark solely based on the quote I am thinking 691 minutes which equals 11 hours and 31 minutes. Okay, I see how you arrived at that figure. I got similar results. But, then? To check my work I looked at the Typical Travel Times table in Book 2, page 1 and see the typical travel time for 100,000 miles at 1-gee to be 2.3 hours. So ... twice as for at 2-gee (a bit less than the actual distance) is still way less than 11+ hours. Even if one triples that figure it is still less. To triple-check. I cross-referenced with the '81 version of the rules. Converting miles to kilometers for the mean distance from Earth to the moon I get 384,472 clicks. Then, looking at the Typical Travel Times tables in Book 2, page 10? I see 129-149 minutes for a similar distance (300,000 and 400,000, respectively). So ... from a bit over 2 hours to less than 3 hours. These figures seem to more or less line up with table values in '77 Traveller. I'm out to sea on this one. I know I'm a proponent of run it your way but I would at least like to understand the rules as written before I head off into my own territory. I thought I would take a stab at it, would have been surprised if I was right. Hopefully one of our experts will explain it to us.
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 3, 2018 22:14:27 GMT -5
]I thought I would take a stab at it, would have been surprised if I was right. Hopefully one of our experts will explain it to us. Hey, I appreciate you giving it a try! I figure it’s something simple I’m overlooking but I can’t figure out what.
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 3, 2018 23:41:20 GMT -5
Okay, here is a good breakdown of the math from over on Google+. It uses metric units, but the math checks out. It’s been a bit too long since physics class, I made a fundamental error setting up the equation. ETA: another poster plugged in English measurements. Just in case you don’t like metric.
|
|
|
Post by Admin Pete on Apr 4, 2018 1:01:49 GMT -5
Okay, here is a good breakdown of the math from over on Google+. It uses metric units, but the math checks out. It’s been a bit too long since physics class, I made a fundamental error setting up the equation. ETA: another poster plugged in English measurements. Just in case you don’t like metric. That link gives me this
|
|
|
Post by dizzysaxophone on Apr 4, 2018 1:03:45 GMT -5
link worked for me. First commentator forgot to multiply the result of the square root by 2 though. Once you've done that you get an answer that lines pretty perfectly with the information in book 2. Y'all got me itching to play some traveller noow!
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 4, 2018 1:05:20 GMT -5
link worked for me. First commentator forgot to multiply the result of the square root by 2 though. Once you've done that you get an answer that lines pretty perfectly with the information in book 2. Y'all got me itching to play some traveller noow! Yes, I noticed that. But he put me on the right track so I didn’t actually say anything.
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 4, 2018 1:06:03 GMT -5
Okay, here is a good breakdown of the math from over on Google+. It uses metric units, but the math checks out. It’s been a bit too long since physics class, I made a fundamental error setting up the equation. ETA: another poster plugged in English measurements. Just in case you don’t like metric. That link gives me this Hmm ... it works for me.
|
|
|
Post by Admin Pete on Apr 4, 2018 2:15:51 GMT -5
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 4, 2018 11:09:36 GMT -5
The first link is the link in the thread for me, the second link is what I get when I pull your post up from Classic Traveller And now, oddly enough? Neither works for me. It did last night but not today. Test case: plus.google.com/u/0/+CameronDuBeers/posts/cCvkLTtW3b3
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 4, 2018 11:16:45 GMT -5
The first link is the link in the thread for me, the second link is what I get when I pull your post up from Classic Traveller And now, oddly enough? Neither works for me. It did last night but not today. Test case: plus.google.com/u/0/+CameronDuBeers/posts/cCvkLTtW3b3Okay ... the link works from the "Recent Posts" screen view, but not the individual thread. What the Gehenna?
|
|
|
Post by True Black Raven on Apr 4, 2018 19:10:27 GMT -5
Well the important part is solved, now if we knew what was going on with Google+ links.
|
|
Deleted
Deleted Member
Posts: 0
|
Post by Deleted on Apr 7, 2018 14:15:19 GMT -5
Okay, mathematics has never been my forté. I've taken (and passed) algebra, calculus, statistics, physics; but it's been a while and an informal poll while I was taking a few of those classes revealed I spent twice as long on the homework as my friends. So, I tried to type up an example of the travel times equation for my house rules document. I'm happy to share it here ... but if anyone sees an issue with the math or how I communicated it please let me know. This in an example Brian Renninger and Winchell Chung gave me over on the G+ Classic Traveller group.
|
|
|
Post by Mighty Darci on May 14, 2018 21:50:54 GMT -5
Have an exalt @piper!
|
|
|
Post by erisred on Jun 6, 2018 14:24:13 GMT -5
Okay, mathematics has never been my forté. I've taken (and passed) algebra, calculus, statistics, physics; but it's been a while and an informal poll while I was taking a few of those classes revealed I spent twice as long on the homework as my friends. So, I tried to type up an example of the travel times equation for my house rules document. I'm happy to share it here ... but if anyone sees an issue with the math or how I communicated it please let me know. This in an example Brian Renninger and Winchell Chung gave me over on the G+ Classic Traveller group. This is correct, with a bit of rounding, if you're flying to Luna and landing there. The final x2 is assuming acceleration to the halfway point followed by deceleration to a stop. If you're accelerating all the way your time to get to that distance would be 73.8 minutes.
|
|
|
Post by mormonyoyoman on Jun 17, 2018 3:07:22 GMT -5
I was good in math and I STILL hated these travel questions.
|
|